The math.
from the equation
pres1/temp1=pres2/temp2
doing a little algebra
(pres1/temp1) X temp2 = pres2
and given the values room temp=70F/21.11C initial pressure=12.5psi ending (game) temp=51F/10.6C
we insert the values, converted to SI (Pascals and Kelvins)
(86,184.5 Pa / 294.3 K) X 283.7 K = 83,080.3 Pa or 12.05 psi
not the 2 psi drop measured.
...but Boomer... it was windy, and wet, surely the wind chill had some effect? No. wind chill is a human perception. There would be minimal evaporative cooling in any case. But let's play with your delusions. Just how cold would it need to be to drop the pressure by 2 psi , to the measured 10.5 psi?
again, doing a little algebra
pres2 / (pres1/temp1) = temp2
72,394.95 Pa / (86,184.5 Pa / 294.3 K) = 274.21 K or 34F