Resistance of the e-match?
I don't like the in series method for this if redundancy is considered, because if one opens up, the entire chain is dead. For this application, I prefer 4 in parallel, but better yet, 2 in parallel on each of 2 independent altimeters.
For a series parallel arrangement, if the match failure rate is 1%, the failure rate of a chain is 2%, and 2 chains in parallel are (2%)^2 = 0.04%.
For the 2 or 4 parallel arrangement, if the match failure rate is 1%, the failure rate of 2 in parallel is (1%)^2 = 0.01%, and 4 in parallel is (1%)^4 = 0.00001%
You also need to consider the failure rate of the altimeter. I
1f it's 1% for a single altimeter, the system failure rate is 2% with 1 e-match and 1% with 2 parallel e-matches.
1f it's 1% for a per altimeter in a dual altimeter system, the system failure rate is 0.04% with 1 e-match per altimeter and 0.01% with 2 parallel e-matches per altimeter.
To answer your current question. for 2S Lipo ~ 8 volts. Current thru 1 e-match is I = V/R.
If R = 1 ohm, I = 8 amps, if R = 2 ohm, I = 4 amps, if R is 3 ohms, I = 2.7 amps, if R= 4 ohms, I = 2.5 amps.
With 4 in parallel, if R = 1 ohm, I = 4 x 8 = 32 amps, if R = 2 ohms, I= 4 x 4 = 16 amps, if R = 3 ohms, I = 4 x 2.7 = 10.8 amps, if R = 4, I = 4 x 2.5 = 10 amps.
1S Lipo ~ 4 volts. Current thru 1 e-match is I = V/R.
If R = 1 ohm, I = 4 amps, if R = 2 ohm, I = 2 amps, if R is 3 ohms, I = 1.3 amps, if R= 4 ohms, I =1.25 amps.
With 4 in parallel, if R = 1 ohm, I = 4 x 4 = 16 amps, if R = 2 ohms, I= 4 x 2 = 8 amps, if R = 3 ohms, I = 4 x 1.3 = 5.4 amps, if R = 4, I = 4 x 1.25 = 5 amps.
Bob