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HMM - tried to set up a poll but it evaporated.........
Went to edit and would not let me add a poll then..... Oh well
Trying to steal a page from NewWay Rockets, except instead of square tubes I'm looking to go triangular.
The rocket I thinking of playing with uses BT5, BT20, and BT50 tubes.
My question gets into sizing the triangles.
I have4 5 options (I used the BT20 for my example in the pix below)
Left Most pix - Area of the triangle = area of the tube
Base length is the same as the tube diameter
Triangle small enough to fit in the tube
Right Most pix - Triangle large enough so the tube would fit inside the triangle
My thoughts
While being able to install the round tube inside the triangle would allow me to strengthen the triangle tube by cheating and inserting a regular circular tube, I think it is too big.
Fitting the triangle inside the tube just makes the triangle too small
I think the real choices are selecting the size to have the same area or having the triangle base length matches the diameter.
A last minute choice I added, but did not draw up, is something in between the Equal Area and the Base=Diameter options.
Then the question would be where in the middle (average?)
Thanks
Les
Went to edit and would not let me add a poll then..... Oh well
Trying to steal a page from NewWay Rockets, except instead of square tubes I'm looking to go triangular.
The rocket I thinking of playing with uses BT5, BT20, and BT50 tubes.
My question gets into sizing the triangles.
I have
Left Most pix - Area of the triangle = area of the tube
Base length is the same as the tube diameter
Triangle small enough to fit in the tube
Right Most pix - Triangle large enough so the tube would fit inside the triangle
My thoughts
While being able to install the round tube inside the triangle would allow me to strengthen the triangle tube by cheating and inserting a regular circular tube, I think it is too big.
Fitting the triangle inside the tube just makes the triangle too small
I think the real choices are selecting the size to have the same area or having the triangle base length matches the diameter.
A last minute choice I added, but did not draw up, is something in between the Equal Area and the Base=Diameter options.
Then the question would be where in the middle (average?)
Thanks
Les