Solve the equation by using the formula method. 3y^{2} +7y + 4 = 0

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#### Solution

The given quadratic equation is 3y2 + 7y + 4 = 0.

Comparing the given equation with ax2 + bx + c = 0 we get,

a = 3, b = 7 and c = 4

`y=(-b+-sqrt(b^2-4ac))/(2a)`

`y=(-7+-sqrt(7^2-4ac))/(2(3))`

`y=(-7+-sqrt(49-48))/6`

`y=(-7+-sqrt(1))/6`

`y=(-7+-1)/(6)`

`y=(-7+1)/(6) or y=(-7-1)/(6)`

`y=-6/6=-1 or y=-8/6=-4/3`

`y=-1 or y=-4/3`

Therefore `-1` and `-4/3` are the roots of given equation.

Concept: Nature of Roots

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