This is a part of the calculation where physics and engineering folks get fussy about definitions. Acceleration is NOT motion or speed or velocity, it is
the rate of change of speed or velocity, per unit of time. Acceleration of an object is directly proportional to its mass and to the forces acting on the object. The equation is a simple one: (Force) = (mass) x (accel). If you do much work at all with physics or engineering you will learn this one for sure. (Some men murmur the names of women in their sleep. Engineers mumble “F = (m) (a)”
This is the point in the analysis where a free-body diagram must be used to summarize the forces acting on the object, which is our rocket. In this diagram we identify all the things that are pulling on the rocket, including motor thrust, weight of the rocket due to Earth’s gravity, and aerodynamic drag. You could account for other forces (like buoyancy, or the weight of the rocket due to Jupiter’s gravity) but these effects will be far smaller in magnitude and can safely be ignored. Did I mention earlier that I am a big fan of simple?
(Bonus points for anyone who correctly constructs a free-body diagram of a rocket in vertical flight and posts it on this thread)
The free-body diagram is a graphic means of summarizing these effects, leading to a calculation in equation form. Assuming the rocket’s orientation is vertical, and all motion is vertical, and we have no crosswinds, then total thrust is acting vertically upward, weight is acting vertically downward, and total aerodynamic drag is acting rearward (vertically downward). We can write an equation describing the total of these forces as:
Net Force = (ThrustT) – (Weight) – (DragT)
where the upward direction is positive. If we can identify what these three forces are at any point in time during the flight then we can use this equation to estimate the total or net force. We also know, at all those time increments, the mass of the rocket, and we can turn around the “F = m a” equation to find acceleration:
a = F / m
Units of all this stuff: accel is expressed in meters / (second-squared)
mass is expressed in kilograms
Force is expressed in Newtons, or (kilogram-meters) / (second-squared)
By using this free-body diagram I am basically analyzing a simple condition of purely vertical flight. If you want to make things more complicated, have at it. If the rocket is launched at some small angle A away from vertical, it is possible to model the vertical components of the resulting flight (horizontal components will result in some sideways “drift” across the launch field, which may or may not be of concern).
For the case where the flight path is deflected at A degrees away from vertical, the vertical component of the motor thrust that is lifting the rocket vertically is (ThrustV) = (ThrustT) x (cosine A)
The vertical component of the weight acting on the rocket is…..Weight = Weight (duh). The trick here is that the orientation of gravity remains vertical regardless of where the rocket is pointed or where it is moving.
The vertical component of the drag acting on the rocket is (DragV) = (DragT) x (cosine A)
For small angles away from vertical (small values of A) the cosine will be very close to 1.0 and the effects of a non-vertical flight path will be negligible. The flight path would have to be eight degrees away from vertical before the value of cosine(8) reaches 0.99 and the vertical components would even be one percent smaller. The flight path would have to be 11 degrees away from vertical before the value of cosine(11) approaches 0.98 and the difference would be two percent smaller. These deflections away from vertical are fairly large, and certainly possible if you launch on a windy day, but they are certainly not desirable if you are striving for altitude. I do not include these effects in the following spreadsheet. I would have to be convinced first that all the assumptions and caveats and approximations that I already made in the rest of the spreadsheet still give me an answer that is better than 99 percent accurate before I start worrying about a little lateral motion (IF it is only a little). If you need to model the effects of non-vertical flight paths on vertical motion, you will probably need someone to video your rocket’s trajectory (from well off to the side, to get a good view of any pitch-over) and make appropriate adjustments to the model at the approximate altitudes (or elapsed time points) in the flight.
(Double-bonus points for anyone who correctly constructs a free-body diagram of a rocket ascending on a path that is “A” degrees away from vertical, and posts it on this thread)
A small simplifying assumption I am going to make is that there is no force resulting from the rocket sliding up the launch rod (or rail), that this part of the launch is frictionless and does not affect the calculation. In the real world this assumption is not too far off the mark, because the lugs
should be properly aligned and the rod
should be straight and the motor thrust line
should be acting straight up through the center of the rocket and there
should be minimal drag caused by the launch rod. If this is not the case, go back and fix something.
I am also going to assume that stupid stuff like electrical launch leads do not snag on the rocket or fins and that the igniter burns cleanly and the leads fall away freely. I think an event such as these would qualify for a “do-over” that even your instructor would have to agree with.
How does all this fit into the spreadsheet? Open the sheet below, go to Column L, pick out a line (from 26 on) and click on a spreadsheet cell. You should see an equation appear in the header window near the top, showing that
Accel (in Col L) = [ motor thrust (in Col D) – aero drag (in Col F) – weight (in Col J) ] divided by mass (in Col I)
The values of aerodynamic drag have not yet been estimated but the equation form can be seen to parallel the same equation F = (m) (a) as I showed you earlier. As we complete more of the spreadsheet and estimate aero drag, the sheet (as already programmed) will adjust itself for the added information automatically.
Note that the value of accel at time = 0.0 (before the motor ignites and generates any thrust, and before the rocket is moving and generates any aero drag) reflects the same value as the gravitational constant. Also notice how quickly and how greatly the values of accel change through the first 0.2 seconds of the motor burn, confirming our earlier suspicion that we would need very short time increments for our model to accurately account for the rapid thrust peak of this motor.
View attachment 10_acceleration_step_05.xlsx