JimJarvis50
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It's relatively easy to determine if your shunt is sufficient. A simple example.....
I use a 9-volt alkaline battery for my altimeters (I specifically do not use LiPo's in this service). The maximum current a 9-volt battery can produce is around 5 amps. The statistics for the JTEK ematches I use are:
- Maximum no fire - 300 ma
- Minimum all fire - 750 ma
- Maximum recommended test current - 40 ma
- Recommended firing current - 1000 ma
Let's say that the resistance for the ematch part of the circuit is 2 ohms (the match and some wire). If my shunt wiring is 1 foot long and I use 24 gauge wire, the resistance of the shunt could be as low as 0.026 ohms, depending on the switch used. If the altimeter fires and shorts the battery to the ematch, the maximum possible current through the ematch would be 0.026 / 2.026 x 5 = 64 ma. This is above the maximum recommended test current but well below the maximum no fire current. And, since the circuit has some actual resistance, the battery won't actually produce 5 amps.
In the above scenario, the shunt would prevent the ematch from firing if the altimeter fires. However, if you used a battery or cap that could source more current, or a longer piece of wire for the shunt, or finer wire, you could approach the maximum no fire current. I ran this test case with 4 feet of wire (0.104 ohms) and a shorter ematch (1.4 ohms perhaps), which might have given 0.104 / 1.504 x 5 = 346 ma. That fired the match.
Although my example case would be safe, I have gone to adding a resistor to the ematch pathway for sustainer ignitors. For a 9 volt battery, and with a recommended firing current of 1 amp, the ematch circuit could have a resistance of as much as 9 ohms. I use a 3 ohm resistor (plus or minus), giving 5 ohms total, to drop the maximum current to below the recommended maximum test current.
Jim
I use a 9-volt alkaline battery for my altimeters (I specifically do not use LiPo's in this service). The maximum current a 9-volt battery can produce is around 5 amps. The statistics for the JTEK ematches I use are:
- Maximum no fire - 300 ma
- Minimum all fire - 750 ma
- Maximum recommended test current - 40 ma
- Recommended firing current - 1000 ma
Let's say that the resistance for the ematch part of the circuit is 2 ohms (the match and some wire). If my shunt wiring is 1 foot long and I use 24 gauge wire, the resistance of the shunt could be as low as 0.026 ohms, depending on the switch used. If the altimeter fires and shorts the battery to the ematch, the maximum possible current through the ematch would be 0.026 / 2.026 x 5 = 64 ma. This is above the maximum recommended test current but well below the maximum no fire current. And, since the circuit has some actual resistance, the battery won't actually produce 5 amps.
In the above scenario, the shunt would prevent the ematch from firing if the altimeter fires. However, if you used a battery or cap that could source more current, or a longer piece of wire for the shunt, or finer wire, you could approach the maximum no fire current. I ran this test case with 4 feet of wire (0.104 ohms) and a shorter ematch (1.4 ohms perhaps), which might have given 0.104 / 1.504 x 5 = 346 ma. That fired the match.
Although my example case would be safe, I have gone to adding a resistor to the ematch pathway for sustainer ignitors. For a 9 volt battery, and with a recommended firing current of 1 amp, the ematch circuit could have a resistance of as much as 9 ohms. I use a 3 ohm resistor (plus or minus), giving 5 ohms total, to drop the maximum current to below the recommended maximum test current.
Jim
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